(x^2-3x-10)(4x+5)=0

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Solution for (x^2-3x-10)(4x+5)=0 equation: 


Simplifying
(x2 + -3x + -10)(4x + 5) = 0

Reorder the terms:
(-10 + -3x + x2)(4x + 5) = 0

Reorder the terms:
(-10 + -3x + x2)(5 + 4x) = 0

Multiply (-10 + -3x + x2) * (5 + 4x)
(-10(5 + 4x) + -3x * (5 + 4x) + x2(5 + 4x)) = 0
((5 * -10 + 4x * -10) + -3x * (5 + 4x) + x2(5 + 4x)) = 0
((-50 + -40x) + -3x * (5 + 4x) + x2(5 + 4x)) = 0
(-50 + -40x + (5 * -3x + 4x * -3x) + x2(5 + 4x)) = 0
(-50 + -40x + (-15x + -12x2) + x2(5 + 4x)) = 0
(-50 + -40x + -15x + -12x2 + (5 * x2 + 4x * x2)) = 0
(-50 + -40x + -15x + -12x2 + (5x2 + 4x3)) = 0

Combine like terms: -40x + -15x = -55x
(-50 + -55x + -12x2 + 5x2 + 4x3) = 0

Combine like terms: -12x2 + 5x2 = -7x2
(-50 + -55x + -7x2 + 4x3) = 0

Solving
-50 + -55x + -7x2 + 4x3 = 0

Solving for variable 'x'.

The solution to this equation could not be determined.

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